Question

surface area of revolution y=(4-x^2/3)^3/2 about the xaxis over [2,8].

Answer #1

Find the surface area of revolution for y = 2
√x over (2,4), about the x-axis.

Compute the surface area of revolution about the x-axis over the
interval [0,π] for y=4sin(x)
(Use symbolic notation and fractions where needed.)

Find the area of the surface of revolution that is generated by
revolving the curve x= (y^4)/8 + (y^-2)/4, from y=2 to y=5, about
the line x=-1

Calculate the area of the surface of revolution when the
function is revolved about the x-axis. Let ? = ?^2 (Q1) over the
interval 0 ≤ ? ≤ 3.
a) Setup the integral with respect to dx
b) Setup the integral with respect to dy

Section 2 Problem 4:
a)Find the area of the surface obtained by rotating the
curvex=1/3((y^2)+2)^(3/2), 1<=y<=2, about the x-axis
b)Find the area of the surface generated by revolving the given
curve about the y-axis. x=sqrt(25-y^2), -4<=y<=4

Calculate the area of the surface bounded by y = x^3 and y =
−2x^2 + 3x
(area between curves)

Find the exact area of the surface obtained by rotating the
curve about the x-axis.
A. y = sqrt(1+ex ) , 0 ≤ x ≤ 3
B. x = 1/3(y2+2)3/2 , 4 ≤ x ≤ 5

find area of surface by rotating the curve y=x^2, from [0,1]
about the y-axis

Calculate the rotational inertia about the x-axis of a
solid of revolution y = x^2 about the y-axis with a height of 4 m.
Assume the solid is made of aluminum (? = 2.7 g/cm3)

Find the mass of a solid of revolution y = x^2 about the y-axis
with a height of 4 m. Assume the
solid is made of aluminum (? = 2.7 g/cm3)

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