Question

Sketch the region enclosed by the given curves and find its
area:

a)y=x^2-4

b)y=x+2 1<=x<=4

Answer #1

Sketch the region enclosed by the curves and find its area.
y=x,y=4x,y=−x+2
AREA =

Sketch the region enclosed by the curves y=x(1-x) and y=-9x+9
then compute its area.

1- Find the area enclosed by the given curves.
Find the area of the region in the first quadrant bounded on the
left by the y-axis, below by the line above left
by y = x + 4, and above right by y = - x 2 + 10.
2- Find the area enclosed by the given curves.
Find the area of the "triangular" region in the first quadrant that
is bounded above by the curve , below by the curve y...

Sketch the region enclosed by the given curves. Decide whether
to integrate with respect to x or y. Draw a
typical approximating rectangle and label its height and width. (Do
this on paper. Your instructor may ask you to turn in this
graph.)
y=4+2sqrtx , y=8/2+x/2
Then find the area S of the region.
S=

Sketch the region enclosed by the given curves. y = |9x|, y = x2
− 10
And find the area

Sketch the region enclosed by the given curves. Draw a typical
approximating rectangle and label its height and width and shade
the area. Lastly, find its area.
1.) y = 3x + 2, y = 14 −
x2, x =
−1, x = 2
2.) y = 9 cos(πx), y = 8x2 −
2
3.) y = |5x|, y = x2 − 6

Find the area of the region enclosed by the curves x=2y and
4x=y^2

Sketch the region enclosed by the given curves, decide whether
to integrate with respect to x or y. Draw a typical approximating
rectangle and label its height and width. Then find the volume of
the region rotated about the line y= -1. You do not need to full
solve the integral, just set it up properly
y = (X - 1)2, y = 1

1.Find the area of the region between the curves y= x(1-x) and y
=2 from x=0 and x=1.
2.Find the area of the region enclosed by the curves
y=x2 - 6 and y=3 between their
interaction.
3.Find the area of the region bounded by the curves
y=x3 and y=x2 between their interaction.
4. Find the area of the region bounded by y= 3/x2 ,
y= 3/8x, and y=3x, for x greater than or equals≥0.

Sketch the region enclosed by x = 56 − y^ 2 and x = − y . Then
find the area of the region.

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