Question

solve (x^2+2y^2)dx/dy = xy

Answer #1

Solve: (x^4 – xy^3)dy + (2y^4 – x^3y)dx = 0

Solve the Differential Equation:
(2y^4 + xy)dx - (6x^2) dy= 0

Find a general solution: (dy/dx) = (x+xy^2)/2y

Solve the given differential equations:
a) dy/dx=(x+1)^2
b) (x+1)dy/dx-xy=x^2+x

solve the differential equation
(2y^2+2y+4x^2)dx+(2xy+x)dy=0

solve the bernqoulli equation dy/dx+xy+xy^2=0

Solve the following DE:
x dy/dx + 2y = x^2 - x + 1 ; y(1) = 1/2

Solve the following:
(3x^2 - y^2)dx + (xy - x^3y^-1)dy = 0

Use Green’s theorem to evaluate the integral: ∫(-x^2y)dx
+(xy^2)dy where C is the boundary of the region enclosed by y=
sqrt(9 − x^2) and the x-axis, traversed in the counterclockwise
direction.

solve diffeential equation.
( x2y +xy -y )dx + (x2 y -2 x2)
dy =0 answer x + ln x + x-1 + y- 2 lny = c
dy / dx + 2y = e-2x - x^2 y (0) =3 answer
y = 3 e -2s + e-2x ( intefral of e
-s^2ds ) s is power ^ 2 means s to power of
2

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