Question

By using method of variation of parameters the particular
solution of the following differential equation

y″+y=sec2(x)

is

Answer #1

Find the general solution to the following differential equation
using the method of variation of parameters.
y"-2y'+2y=ex csc(x)

Use the method of variation of parameters to find a particular
solution of the differential equation y′′−8y′+15y=32et.

Find only the particular solution of the given differential
equation by using variation of parameters and Wronskians.
y ' ' - y = csc x cot x

Find a particular solution for the differential equation by
variation of parameters.
y''- y' -2y = e^3x , y(0) = -3/4 , y'(0)=15/4

differential equations!
find the Differential Equation General Solve by using
variation of parameters method...
y''' - 3y'' +3y' - y =12e^x

3. Find the general solution if the given differential equation
by using the variation of parameters method. y''' + y'= 2 tan x, −
π /2 < x < π/2

Use the method of variation parameters to find the
general solution of the differential equation
y'' +16y = csc 4x

Find a solution to y^''-4y^'-5y=2e^2t using variation of
parameters. Find the solution to the differential equation in
problem 6, this time using the method of undetermined
coefficients.

) Solve the differential equation
dydt=
cos(t)y+sin(t)
using either the method of variation of parameters or the method of
integration factor. Clearly identify the integration factor or
parameter v(t) used (depending on which method you use).
Also identify the solution to the homogeneous equation, and the
particular solution. The use your solution to find the solution to
the IVP obtained by adding the initial condition y(0) = 1.

Solve Differential equation by variation of parameters method.
y"-5y'+6y=e^x

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