Question

Suppose that f(x) = (2x)/((4-2x)^3)

Find an equation for the tangent line to the graph of f at x=1.

Tangent line: y =

Answer #1

f(x)=1/2x ln x^4, (-1,0)
a) find an equation of the tangent line to the graph of the
function at the indicated point.
b) Use a graphing utility to graph the function and its tangent
line at the point.

1.) Find the equation of the tangent line to the graph of the
function f(x)=5x-4/2x+2 at the point where x=2
2.) Find the derivative: r(t)=(ln(t^3+1))^2

let f(x) = sqrt x^4+4x+4.find the equation of the tangent line
to the graph of f −1(a) when a = 3

1. Let f(x)=(x^2+1)(2x-3)
Find the equation of the line tangent to the graph of f(x) at
x=3.
Find the value(s) of x where the tangent line is horizontal.
2. The total sales S of a video game t months after being
introduced is given by the function
S(t)=(5e^x)/(2+e^x )
Find S(10) and S'(10). What do these values represent in terms
of sales?
Use these results to estimate the total sales at t=11 months
after the games release.

Find an equation of the tangent line to the graph of
2x+5/(1-2x)^3 at the point (-1,1)

determine the equation of tangent line to the graph of
y=tan(1/2x)+xcot(2x+pi/4) at x=pi/2

Find an equation of the line that is tangent to the graph of
f and parallel to the given line.
Function
Line
f(x) = x2
6x − y + 9 = 0

a) Find the equation of the tangent line to f(x) = e –x at the
point (1, e –1).
b) Find the equation of the tangent line to f(x) = 3x2 – 2x + 5 at
x = 2.

Find the equation of the tangent line to the graph of the
function f(x)=(x^2+8)(x−2) at the point (1,−9).
I thought it was re-writen as (2x^2 + 8)(x-2) then plugging in 1
for x and solving. I came up withit in slope form y = -20x - 1 but
says im wrong. What steps did i miss?

find a point of the graph of the function f(x) = e^2x such that
the tangent line to the graph at that point passes through the
origin. Use a graphing utility to graph f and the tangent line is
the same viewing window

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