Question

An arrow is propelled upward at 98 m/sec2 , (height in meters after t seconds is...

An arrow is propelled upward at 98 m/sec2 , (height in meters after t seconds is given by h = -4.9t2 + 98)t:

a. Graph the equation on the given coordinate system.

b. Use the leading coefficient to describe the end behavior.

c. State the domain and range of the function.

d. What is the vertex? What does this signify?

e. Set up and solve the inequality for the interval of time the arrow will be higher than 445.9m.

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
If an object is propelled upward from a height of s feet at an initial velocity...
If an object is propelled upward from a height of s feet at an initial velocity of v feet per second, then its height h after t seconds is given by the equation h=−16t^2+vt+s, where h is in feet. If the object is propelled from a height of 1212 feet with an initial velocity of 9696 feet per second, its height h is given by the equation h =minus−16t^2+96 +12. After how many seconds is the height 120 feet?
If an arrow is shot upward on the moon with a velocity of 52 m/s, its...
If an arrow is shot upward on the moon with a velocity of 52 m/s, its height (in meters) after t seconds is given by H = 52t − 0.83t2. (a) Find the instantaneous velocity of the arrow after one second. Correct: Your answer is correct. m/s (b) Find the instantaneous velocity of the arrow when t = a. m/s (c) At what time t will the arrow hit the moon? (Round your answer to two decimal places.) t =...
The height of a projectile, h, in meters, compared to time, t, in seconds, from a...
The height of a projectile, h, in meters, compared to time, t, in seconds, from a launch is given by the equation h (t) = -4.9t^2 + 13t + 4.3 a) Calculate its average speed during the 2nd second b) Calculate its instantaneous speed exactly 2 seconds after launching (without derivatives)
If an arrow is shot upward on Mars with a speed of 67 m/s, its height...
If an arrow is shot upward on Mars with a speed of 67 m/s, its height in meters t seconds later is given by y = 67t − 1.86t2. Find the average speed over the given time intervals. (i)     [1, 2] (ii)     [1, 1.5] (iii)     [1, 1.1] (iv)     [1, 1.01] (v)     [1, 1.001] Step 1 Recall that the average speed between times t1 and t2 is calculated usingvave = y(t2) − y(t1) t2 − t1 .We are given that y...
If an arrow is shot upward on Mars with a speed of 67 m/s, its height...
If an arrow is shot upward on Mars with a speed of 67 m/s, its height in meters t seconds later is given by y = 67t − 1.86t2. Find the average speed over the given time intervals. (i)     [1, 2] (ii)     [1, 1.5] (iii)     [1, 1.1] (iv)     [1, 1.01] (v)     [1, 1.001] Step a Recall that the average speed between times t1 and t2 is calculated usingvave = y(t2) − y(t1) t2 − t1 .We are given that y...
An object is launched upward from a platform so that its height (in feet) above the...
An object is launched upward from a platform so that its height (in feet) above the ground t seconds after it is launched is given by the function h(t)=-16t^2 +160t+176. a. When does the object reach its maximum height? What is the maximum height? b. When does the object hit the ground? c. What is the domain and range of this function (given the context)? d. Sketch an accurate graph of this function in an appropriate window. Mark on your...
NASA launches a rocket at t=0 seconds. Its height, in meters above sea-level, as a function...
NASA launches a rocket at t=0 seconds. Its height, in meters above sea-level, as a function of time is given by h(t)=−4.9t^2+277t+283 Assuming that the rocket will splash down into the ocean, at what time does splashdown occur? How high above sea-level does the rocket get at its peak?
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT