Consider the non-homogeneous equation y(4)−4y(3)+5y′′−4y′+4=2e2t+sinty(4)−4y(3)+5y″−4y′+4=2e2t+sint. The general solution of the corresponding homogeneous equation is yh=c1e2t+c2te2t+c3cost+c4sintyh=c1e2t+c2te2t+c3cost+c4sint. What is the form of a particular solution ypyp?
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