A mass weighing 32 pounds stretches a spring 2 feet. The mass is initially released from rest from a point 1 foot below the equilibrium position with an upward velocity of 2ft/sec. find the equation of the motion and solve it, determine the period and amplitude.
Solution-
kX2=32
k=16
Assume equation of motion-
Position,
t=0 , y=-1ft
.....(1)
Velocity
v=2 at t=0
......(2)
Use energy conservation,
A = 3
Substitute in equation 1,
Substitute in equation 2
Time period T is,
T= 8.887 s
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