A manufacturer knows that their items have a normally
distributed length, with a mean of 9.1 inches, and standard
deviation of 1.4 inches.
If one item is chosen at random, what is the probability that it is
less than 8.5 inches long?
First, we will need to find the Z-Score
where X = Required Probability, = mean, = standard deviation
Therefore, Substituting the Values,
z = -0.42857
Further, We will look-up a Standard Z-Table and find the Area Corresponding to this value
Since we have been asked Probability of being Less than 8.5 inches, so we need P(X<Z)
From any standard Z-Table, we can find this to be:
P(X < Z) = 0.33412
This means the Probability that it will be less than 8.5 inches is 0.33412
i.e. 33.412% will be less than 8.5 inches.
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