Question

Section 2 Problem 4:

a)Find the area of the surface obtained by rotating the curvex=1/3((y^2)+2)^(3/2), 1<=y<=2, about the x-axis

b)Find the area of the surface generated by revolving the given curve about the y-axis. x=sqrt(25-y^2), -4<=y<=4

Answer #1

Find the exact area of the surface obtained by rotating the
curve about the x-axis.
A. y = sqrt(1+ex ) , 0 ≤ x ≤ 3
B. x = 1/3(y2+2)3/2 , 4 ≤ x ≤ 5

Find the exact area of the surface obtained by rotating the
curve x = 1-2y^2, 1 ≤ y ≤ 2, about x-axis.

Find the area of the surface obtained by rotating the curve y =
3x3 from x = 0 to x = 3 about the x-axis.
The area is _____ square units.

Find the area of the surface obtained by rotating the following
curve about the x axis.
y = sin(1/2*x) 0<=x <= pi

Find the exact area of the surface obtained by rotating the
curve about the x axis.
1. Original problem y= x^3 from 0 < x < 2
I got up to the SA= 2 pi the integral of 1 to 145 of (x^3)(the
square root of (1+9x^4))dx
I don't know how to integrate from this part on to get the exact
answer.

Find the exact area of the surface obtained by rotating the
curve about the x -axis.
y = sin π x/ 5 , 0 ≤ x ≤ 5

find the surface area of the object obtained by rotating y=4-x,
1 ≤ x ≤ 6

1- Find the area enclosed by the given curves.
Find the area of the region in the first quadrant bounded on the
left by the y-axis, below by the line above left
by y = x + 4, and above right by y = - x 2 + 10.
2- Find the area enclosed by the given curves.
Find the area of the "triangular" region in the first quadrant that
is bounded above by the curve , below by the curve y...

find area of surface by rotating the curve y=x^2, from [0,1]
about the y-axis

Find the area of the surface obtained by rotating the curve
?=5?^2y
from ?=0 to ?=8 about the y-axis.

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