Answer :
Consider the given system of equations
6A + 2T = 6 ---------- ( 1 )
8A - 4T = 28 ---------- ( 2 )
Multiply the equation ( 1 ) by 2 and add to the equation ( 2 ) , we get
12A + 4T = 12
8A - 4T = 28
------------------------
20A = 40
Dividing by 20 on both sides we get
A = 2
Substituting A = 2 in equation ( 1 ) , we get
6(2) + 2T = 6
12 + 2T = 6
subtract 12 on both sides , we get
2T = - 6
Dividing by 2 we get
T = - 3
Therefore , the solution of the system of equations is A = 2 and T = - 3
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