Question

Find dy/dx if y= tan(sinx)

Answer #1

**Answer:**

**Solution:**

**Step 1.**

Differentiate w.r.t. x.

............... Multiply numerator and denominator by d (sinx).

**Step 2. Let t = sinx .**

**Step 3.**

.......... using &

**Step 4. Put t = sinx.**

Y cosx dx + (2Y - sinx)dy=0

Find the solution of the following differential
equation:
(?^3 y/dx^3)-7(d^2 y/dx^2)+10(dy/dx)=e^2x sinx

1.Given that y = x + tan−1 y , find dy dx
2.Determine the equation of the tangent line to the curve y = (2
+ x) e −x at the point (0, 2)

Find the general solution and initial value solution: (cos x)dy
= -2y2(tan x)dx, y(0)=1/6

Find dy/dx by implicit differentiation. tan−1(3x2y) = x +
4xy2

Use this equation to find
dy/dx.
8 tan−1(x2y) = x + xy2

find dy/dx. yo do not need to simplify.
1. 4cos(x)sin(y)+tan(x/y)=1+x+y
2. x/y=cosx
Please show work.

Solve the initial value problems.
1) x (dy/dx)+ 2y = −sinx/x , y(π) = 0.
2) 3y”−y=0 , y(0)=0,y’(0)=1.Use the power series method
for this one . And then solve it using the characteristic
method
Note that 3y” refers to it being second order
differential and y’ first

Find dy/dx of y=x^2cos^4(x)

Homogenous Differential Equations:
dy/dx = y - 4x / x-y
dy/dx = - (4x +3y / 2x+y)

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