Question

Find the surface area of the part of the sphere
*x*^{2} + *y*^{2} +
*z*^{2} = 49 that lies above the plane *z*
= 4.

Answer #1

Find the area of the surface. The part of the sphere x2 + y2 +
z2 = 64 that lies above the plane z = 3.

Find the area of the part of the cylinder
x2+y2=2ax that lies inside the sphere
x2+y2+z2=4a2 by a
surface integral.
Please step by step solution

Evaluate the area of the part of the conical surface
x2 + y2 = z2 bounded below by the
sphere x2 + y2 + z2 = 4 and above
by the plane 2x + y + 10z = 20. Derive the final form of the
integral.

Find the surface area of upper part of the sphere of radius a,
x2 + y2 + z2 = a2, cut
by the cone z = sqrt(x2 + y2). Show the
integral that corresponds to the surface area using spherical
coordinates.

Find a parametric representation for the surface.
The part of the sphere
x2 +
y2 + z2 =
16
that lies above the conez =
x2 + y2
. (Enter your answer as a comma-separated list of equations. Let
x, y, and z be in terms of u
and/or v.)
where z >
x2 + y2

Find the surface area of the cone x2 + y2
= z2 that lies inside the sphere x2 +
y2 + z2 = 6z by taking integrals.

Find the area of the surface.
The portion of the sphere
x2 + y2 + z2 = 400
inside the cylinder
x2 + y2 = 256
*its not 320pi or 1280pi

Find the area of the following part of the surface z = x + y2
that lies above the triangle with vertices (0,0), (1,1), and
(0,1).

Let W be the region above the sphere
x2 +
y2 + z2 =
6
and below the paraboloid
z = 4 − x2 −
y2.
Compute the volume of W using cylindrical coordinates.
(Round your answer to two decimal places.)

Compute the surface integral over the given oriented
surface:
F=〈0,9,x2〉F=〈0,9,x2〉 , hemisphere
x2+y2+z2=4x2+y2+z2=4, z≥0z≥0 , outward-pointing
normal

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