Question

An isosceles triangular plate of base 10 ft. and height 8 ft. is submerged vertically in water with its base at the top parallel to and 2 ft. below the surface. If the water has weight-density 64 lb/ft364 lb/ft3. How much force is the water exerting on one side of the plate?

I've tried and gotten to the formula ∫(64x(5/4)(2-x) ) but I think I have the wrong limits on my integral. Can you help explain which limits I should use?

Answer #1

A triangular plate with base 6 m and height 2 m is submerged
vertically in water such that the highest vertex of the plate is 4
meters below the surface and the base is horizontal to the
surface.
4 m ( from water surface to top of triangle )
6 m ( triangle width )
2 m (triangle height )
Express the hydrostatic force against one side of the plate as
an integral and evaluate it. (Round your answer to...

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Please help me with this. My answer is 690900.

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the total fluid force ? on a side of the valve. b. Calculate the
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water and ? =...

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