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An isosceles triangular plate of base 10 ft. and height 8 ft. is submerged vertically in...

An isosceles triangular plate of base 10 ft. and height 8 ft. is submerged vertically in water with its base at the top parallel to and 2 ft. below the surface. If the water has weight-density 64 lb/ft364 lb/ft3. How much force is the water exerting on one side of the plate?

I've tried and gotten to the formula ∫(64x(5/4)(2-x) ) but I think I have the wrong limits on my integral. Can you help explain which limits I should use?

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