Question

(x2+2)y^'' + 4xy^' + 2y = 0 , y(0) =0 , y^'(0) = 1 Solve by...

(x2+2)y^'' + 4xy^' + 2y = 0 , y(0) =0 , y^'(0) = 1

Solve by using power series around x0= 0

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
solve this series 1. 2y'' - 3xy = 0 2. (x2+1)y'' - 4xy' + 6y =...
solve this series 1. 2y'' - 3xy = 0 2. (x2+1)y'' - 4xy' + 6y = 0
Solve y''+4xy'-y=0 using the power series method (frobenius)
Solve y''+4xy'-y=0 using the power series method (frobenius)
In Exercises 31-42, solve the initial value problem. 3(x^(2))y''-4xy'+2y=0, y(1)=2, y'(1)=1
In Exercises 31-42, solve the initial value problem. 3(x^(2))y''-4xy'+2y=0, y(1)=2, y'(1)=1
7) (1 − x2)y'' − 2xy' + 2y = 0; y(0) = 0, y'(0) = 3...
7) (1 − x2)y'' − 2xy' + 2y = 0; y(0) = 0, y'(0) = 3 Find the power series solution about x=0.
Solve the initial value problem. (?2+1)?′+2?=1+?where?(0)=2(x2+1)y′+2y=1+xwherey(0)=2
Solve the initial value problem. (?2+1)?′+2?=1+?where?(0)=2(x2+1)y′+2y=1+xwherey(0)=2
1) Solve by power series around x=0: y"-2xy'-2y=0 (Find the first three nonzero terms of each...
1) Solve by power series around x=0: y"-2xy'-2y=0 (Find the first three nonzero terms of each of the LI solutions)
solve y''-3y'+2y=0 using power series please
solve y''-3y'+2y=0 using power series please
Solve the initial value problems. 1) x (dy/dx)+ 2y = −sinx/x , y(π) = 0. 2)...
Solve the initial value problems. 1) x (dy/dx)+ 2y = −sinx/x , y(π) = 0. 2) 3y”−y=0 , y(0)=0,y’(0)=1.Use the power series method for this one . And then solve it using the characteristic method Note that 3y” refers to it being second order differential and y’ first
solve diffeential equation. ( x2y +xy -y )dx + (x2 y -2 x2) dy =0 answer...
solve diffeential equation. ( x2y +xy -y )dx + (x2 y -2 x2) dy =0 answer x + ln x + x-1 + y- 2 lny = c dy / dx + 2y = e-2x - x^2 y (0) =3 answer y =  3 e -2s + e-2x ( intefral of e -s^2ds ) s is power ^ 2 means s to power of 2  
Solve using transforms. y''' +2y''-y'-2y=24e^-3t + 48t^2; y(0) = y'(0) = y''(0) = 0
Solve using transforms. y''' +2y''-y'-2y=24e^-3t + 48t^2; y(0) = y'(0) = y''(0) = 0
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT