If an arrow is shot upward on Mars with a speed of 67 m/s, its height in meters t seconds later is given by
y = 67t − 1.86t2.
Find the average speed over the given time intervals.
(i) | [1, 2] |
(ii) | [1, 1.5] |
(iii) | [1, 1.1] |
(iv) | [1, 1.01] |
(v) | [1, 1.001] |
Step 1
Recall that the average speed between times
t1
and
t2
is calculated usingvave =
y(t2) − y(t1) |
t2 − t1 |
.We are given that
y = 67t − 1.86t2.
Evaluating at
t = 1,
we have
y(1) = 67(1) − 1.86(1)2 = 65.14.
Thus, the average speed between times 1 and 1 + h is as follows.
vave | = |
|
Get Answers For Free
Most questions answered within 1 hours.