Question

Solve for undetermined coefficients:

y'''-y''-4y'+4y=5 - e^x +e^2x

Answer #1

Solve by undetermined coefficients (superposition approach)
y''- 4y'+4y = e^(4x)+xe^(-2x)
y(0) = 1
y'(0)= -1

Solve the given differential equation by undetermined
coefficients.
y''− 4y = 8e^(2x)

Solve a Differential Equation by the Method of Undetermined
Coefficients.
y'' - 4y= 2-8x-cos(2x)

Solve the given initial value problem by undetermined
coefficients (annihilator approach).
y'' − 4y' + 4y = e^4x + xe^−2x
y(0) = 1
y'(0) = −1

Solve the given differential equation by undetermined
coefficients.
4y'' − 4y' −
35y = cos(2x)

solve the given differential equation by undetermined
coefficients. y"-y'-2y=e^2x

Solve using the method of undetermined coefficients.
y′′ − y′ − 2y = 3 + e^(2x)

Use the method of undetermined coefficients to solve:
y''+3y'-4y=(e^t)+2(e^-(5t))

Use undetermined coefficients to solve the differential
equation
y'' + y = x sin 2x

Solve using undetermined coefficients - superposition
approach:
y" - 4y' + 5y = 6cos(x) + 7sin(x)

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