Solve the psuedo-quadratic equation y^4+7y^2-30=0
Given equation y^4+7y^2-30=0
put x=y^2
Therefore, the equation becomes
x^2+7x-30=0
x^2+10x-3x-30=0
x(x+10) -3(x+10)=0
(x-3)(x+10)=0
Hence
(x-3)=0 or (x+10)=0
x=3 or x=-10
put y^=x
y^2 = 3 or y^2 = -10
hence,
or
Get Answers For Free
Most questions answered within 1 hours.