Question

The object starts moving along a straignt line from point A with velocity v(t)=(t-2), where time t is measured in seconds and v(t) in meters per second.

A- How far from A is the object going to be 11 seconds from the start?

B-What distance is the object going to cover in the first 11 seconds?

Answer 1

Step 1: Find the point where object will change it's direction, which will be when

V(t) = 0

V(t) = t - 2 = 0

t = 2 sec

Now since we need distance of object from Point A after 11 sec, So we need to find displacement of object, So

V(t) = dS/dt = (t - 2)

dS = (t - 2)*dt

So object will be 38.5 m from point A after 11 sec.

Part B.

total distance traveled by object will be:

total distance covered by object in 11 sec will be 42.5 m

Let me know if you've any query.