Question

Find the equations for the tangent line and the normal line to
the curve x = sin^2 (xy)? at point ((1/2),(pi/2)).

Answer #1

Find the equations for the tangent line and the normal line to
the curve.
x=sen^2(xy) on the point (1/2,pi/2)
the hell, that is the problem... plese help.
pi=3.14 what else do you need???????????

Find parametric equations for the tangent line to the curve with
the given parametric equations at the specified point.
x =
e−5t
cos(5t), y =
e−5t
sin(5t), z =
e−5t; (1, 0, 1)

Find parametric equations for the tangent line to the curve with
the given parametric equations at the specified point.
x =
e−8t
cos(8t), y =
e−8t
sin(8t), z =
e−8t; (1, 0, 1)

Find parametric equations for the tangent line to the curve with
the given parametric equations at the specified point. x = 6
cos(t), y = 6 sin(t), z = 10 cos(2t); (3 3 , 3, 5)
x(t), y(t), z(t) = ??

Use implicit differentiation to find an equation of the line
tangent to the curve sin(x+y)=2x-y at the point (pi,2\pi )

Find the parametric equations for the tangent line to the curve
that is the intersection of the paraboloid z=4x^2+y^2 and the
parabolic cylinder y=x^2 at the point (1,1,5).

Use implicit differentiation to find an equation of the line
tangent to the curve sin(x+y)=2x-y at the point (pi, 2pi )

find an equation for the line tangent to the given curve at the
point defined by the given value of t.
x sin t + 2x =t, t sin t - 2t =y, t=pi

Find the equations of the tangent and normal to the curve
x2 + y2+3xy-11 = 0 at the point x = 1, y =
2.

Find equations of the tangent plane and normal line to the
surface x=2y^2+2z^2−159x at the point (1, -4, 8).
Tangent Plane: (make the coefficient of x equal to 1).
=0.
Normal line: 〈1,〈1, , 〉〉
+t〈1,+t〈1, ,

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