Question

A chemist wants
to make 24 liters
of a 20.5%
acid

solution. In the
stock room she
finds a 12% acid
solution

and a 32% acid
solution. How many
liters of each
solution

must be mixed to
obtain the desired
solution? Round all

computations to the
nearest thousandth.

Answer #1

Let the chemist needs x litres of 12% acid solution and y litres of 32% acid solution.

Then according to the given data, we have,

x + y = 24................(1)

and, (12x/100) + (32y/100) = (24 * 20.5/100)

i.e. 12x + 32y = 492............(2)

.

Now 32*(1) - (2) gives,

32x + 32y - 12x - 32y = 768 - 492

i.e. 20x = 276

i.e. x = 276/20

i.e. x = 13.8

So from (1), y = 24 - 13.8 = 10.2

.

.

So the chemist needs **13.8 litres** of 12% acid
solution and **10.2 litres** of 32% acid solution.

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