Question

Find y as a function of t if

y′′+6y′+10y=0

y(0)=7, y′(0)=4

y(t)=

Answer #1

Solve
y''+10y'+25y=0, y(0)=−4, y'(0)=25
At what time does the function y(t) reach a maximum?
t =

Find y as a function of x if
y‴−10y″+21y′=0
y(0)=3, y′(0)=1, y″(0)=7
y(x)=?

Find y as a function of x if y(4)−6y‴+9y″=0,
y(0)=12, y′(0)=18, y″(0)=9, y‴(0)=0.
y(x)=?

Find ?y as a function of ?t if
?″+10?′+50?=0,?(0)=9,?′(0)=5.y″+10y′+50y=0,y(0)=9,y′(0)=5.
?=y=
Note: This problem cannot interpret complex numbers. You may need
to simplify your answer before submitting it.

Find y as a function of t if
9y′′−42y′+130y=0,
y(0)=7,y′(0)=5.
y(t)=

Use the laplace transform to solve for the initial
value problem:
y''+6y'+25y=delta(t-7)
y(0)=0 y'(0)=0

use Laplace transforms to solve the integral for y(t)
y"-6y'+5y=(14-8t)e^t
y(0)=3
y'(0)=-4

Find the solution of the given initial value problems.
6y"-5y'+y=0, y(0)=4 , y'(0)=0

Solve the initial value problem 9(t+1) dy dt −6y=18t,
9(t+1)dydt−6y=18t, for t>−1 t>−1 with y(0)=14. y(0)=14. Find
the integrating factor, u(t)= u(t)= , and then find y(t)= y(t)=

a)
find all possible solutions of y''+y'-6y=12t
b) solve initial value problem of y''+y'-6y=12t, y(0)=1,
y'(0)=0

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