Question

Find an equation for the line tangent to the graph of f(x)=sqrt(x)/6x−1 at the point (2,f(2)).

Answer #1

let f(x) = sqrt x^4+4x+4.find the equation of the tangent line
to the graph of f −1(a) when a = 3

f(x)=1/2x ln x^4, (-1,0)
a) find an equation of the tangent line to the graph of the
function at the indicated point.
b) Use a graphing utility to graph the function and its tangent
line at the point.

a) Find the equation of the tangent line to f(x) = e –x at the
point (1, e –1).
b) Find the equation of the tangent line to f(x) = 3x2 – 2x + 5 at
x = 2.

Find an equation of the tangent line to y=cosx at the point (3pi/4,
-sqrt(2)/2). Include hand sketched copy of tangent line and
graph

1.) Find the equation of the tangent line to the graph of the
function f(x)=5x-4/2x+2 at the point where x=2
2.) Find the derivative: r(t)=(ln(t^3+1))^2

1. Find the equation of the tangent line to the graph of ?2? −
5??2 + 6 = 0 at (3,1).
2.. Find the equation of the normal line to the graph of sin(??) =
? at the point (?/2 ,1).
3.. Find the equation of the tangent line to the graph of cos(??) =
? at the point (0.1)
Find implicit differentiation of dy/dx
a) xy=x+y
b) xcosy=y
c)x^3 +y^2=0

Find the equation of the tangent line to the graph of the
function f(x)=cot2x at the point (π/4,0).

Find an equation for the tangent line to the graph of the given
function (-2,-1)
f (x)= x^2 - 5

Find the equation of the tangent line to the graph of y = e x
2−1 at the point (1, 1)

Find the equation of the tangent line to the graph of the
function f(x)=(x^2+8)(x−2) at the point (1,−9).
I thought it was re-writen as (2x^2 + 8)(x-2) then plugging in 1
for x and solving. I came up withit in slope form y = -20x - 1 but
says im wrong. What steps did i miss?

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