Set up, but do not evaluate or simplify, the definite integral(s) which could be used to find the area of the region made up of points inside of both the circle r = cos(θ) and the rose r = sin(2θ)
Given,
Equating both,
The graph is plotted below.
The given function is symmetric about x axis,
There fore the area is twice the area in the first quadrant.
Area of the region of both the circle and the rose is,
There fore total area is twice the above,
Hence the answer.
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