Question

Find the equation of the tangent line to the graph of the function f(x)=cot2x at the point (π/4,0).

Answer #1

f(x)=1/2x ln x^4, (-1,0)
a) find an equation of the tangent line to the graph of the
function at the indicated point.
b) Use a graphing utility to graph the function and its tangent
line at the point.

Find the equation of the line tangent to the graph of the given
function at the point with the indicated x-coordinate.
f(x) = (x0.5 + 8)(x2 + x); x = 1

1.) Find the equation of the tangent line to the graph of the
function f(x)=5x-4/2x+2 at the point where x=2
2.) Find the derivative: r(t)=(ln(t^3+1))^2

Find an equation for the tangent line to the graph of the given
function (-2,-1)
f (x)= x^2 - 5

Find an equation of the line that is tangent to the graph of
f and parallel to the given line.
Function
Line
f(x) = x2
6x − y + 9 = 0

Find the equation of the tangent line to the graph of the given
function at the given value of x:
f(x)= (x^2 +12)^3/4 where x=2. please show work .

Find the equation of the tangent line to the graph of the
function f(x)=(x^2+8)(x−2) at the point (1,−9).
I thought it was re-writen as (2x^2 + 8)(x-2) then plugging in 1
for x and solving. I came up withit in slope form y = -20x - 1 but
says im wrong. What steps did i miss?

find a point of the graph of the function f(x) = e^2x such that
the tangent line to the graph at that point passes through the
origin. Use a graphing utility to graph f and the tangent line is
the same viewing window

Find an equation for the line tangent to the graph of
f(x)=sqrt(x)/6x−1 at the point (2,f(2)).

Suppose that f(x) = (2x)/((4-2x)^3)
Find an equation for the tangent line to the graph of f at
x=1.
Tangent line: y =

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