Question

A) Write a? slope-intercept equation for a line that passes through

(?3,1) and (3,?11).

B) Solve the following equation.

9x?3+5x=5x+5?7x

Answer #1

A). Let the slope-intercept form of the equation for the required line be y = mx+c where m is its slope and c is the y-intercept. Now, the slope of a line that passes through (?3,1) and (3,?11) is (-11-1)/(3+3) = -12/6 = -2 so that m = 2. Then the required equation changes to y = -2x+c. Further, on substituting x = -3 and y = 1 in this equation, we get 1 = (-2)*(-3)+c or, c = 1-6 = -5. Then the slope-intercept form of the equation for the required line is y = -2x-5.

B). We have 9x?3+5x = 5x+5?7x or, 14x-3 = -2x+5 or, 14x+2x = 5+3 or, 16x = 8 so that x = 8/16 = ½.

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