The solid can be formed from an Octahedron via Truncation by removing six Square Pyramids, each with edge slant height and height , where is the side length of the original Octahedron. From the above diagram, the height and base area of the Square Pyramid are
(1) | |||
(2) |
The Volume of the truncated octahedron is then given by the Volume of the Octahedron
(3) |
minus six times the volume of the Square Pyramid,
(4) |
Get Answers For Free
Most questions answered within 1 hours.