Question

exact differential equation, (2xy+x)dx+(x^2+y)dy=0

Answer #1

Solve the following differential equations.
a.) dy/dx+2xy=x, y(0)=2
b.) ?^2(dy/dx)−?y=−y^2

solve the differential equation
(2y^2+2y+4x^2)dx+(2xy+x)dy=0

Homogeneous Differential Equations:
dy/dx = xy/x^(2) - y^(2)
dy/dx = x^2 + y^2 / 2xy

3. Consider the equation (3x^2y + y^2)dx + (x^3 + 2xy + 5)dy =
0. (a) Verify this is an exact equation
(b) Solve the equation

differential equations solve
(2xy+6x)dx+(x^2+4y^3)dy, y(0)=1

Consider the following differential equation: dy/dx =
−(3xy+y^2)/x^2+xy
(a) Rewrite this equation into the form M(x, y)dx + N(x, y)dy =
0. Determine if this equation is exact;
(b) Multiply x on both sides of the equation, is the new
equation exact?
(c) Solve the equation based on Part (a) and Part (b).

(x-y)dx + (y+x)dy =0 Solve the differential equation

test if the equation ((x^4)(y^2) - y)dx + ((x^2)(y^4) - x)dy = 0 is
exact. If it is not exact, try to find an integrating factor. after
the equation is made exact, solve by looking for integrable
combinations

(2xy+x^2+3y^2)dy/dx+(y^2+2xy+3x^2)=0

differential equation(2x+3y)dx+ (y+2)dy=0

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