Question

Find the absolute maximum value and the absolute minimum value of the function f(x,y)=(1+x2)(1−y2) on the disk

D={(x,y) | x2+y2⩽1}

Answer #1

Find the absolute maximum and minimum values of f on
the set D.
f(x, y) =
x2 + y2 +
x2y + 6,
D = {(x,
y) | |x| ≤ 1,
|y| ≤ 1}
absolute maximum value
absolute minimum value

Find the absolute maximum and minimum values of f on
the set D.
f(x, y) =
4x + 6y −
x2 − y2 +
3,
D = {(x,
y) | 0 ≤ x ≤ 4, 0 ≤
y ≤ 5}
absolute maximum value
absolute minimum value

Find the absolute maximum and minimum values of f on
the set D.
f(x, y) =
4x + 6y −
x2 − y2 +
5,
D = {(x,
y) | 0 ≤ x ≤ 4, 0 ≤
y ≤ 5}
absolute maximum value
absolute minimum value

Find the absolute maximum value and absolute minimum value of
f(x,y) = x2 +2y2−2x−4y+1 on the region D = {(x,y) ∈ R2 : 0 ≤ x ≤
2,|y−1.5|≤ 1.5}

Find the absolute maximum value and the absolute minimum value
of the function f ( x , y ) = x 2 y 2 + 3 y on the set D defined as
the closed triangular region with vertices ( 0 , 0 ), ( 1 , 0 ),
and ( 1 , 1 ), that is, the set D = { ( x , y ) | 0 ≤ x ≤ 1 , 0 ≤ y
≤ x }...

Find the absolute maximum and minimum values of f on
the set D.
f(x, y) =
4x + 6y −
x2 − y2 +
2,
D = {(x,
y) | 0 ≤ x ≤ 4, 0 ≤
y ≤ 5}

Find the minimum value of the function f(x,y)=2x+y, subject to
the constraint x2+y2=5.

Find the absolute maximum and absolute minimum values of f(x,y)
= x^2 + 2y^2 − 2x + 2 on the closed disk D: x^2 + y^2 ≤ 4.
Answer: absolute min: f(1, 0) = 1; absolute max: f(−1, ± √3) =
11

Find the absolute maximum, and minimum values of the function:
f(x, y) = x + y − xy Defined over the closed rectangular region D
with vertices (0,0), (4,0), (4,2), and (0,2)

1. Find the absolute maximum value and the absolute minimum
value,if any, of each function.
(a) f(x) = -x2+ 4x + 6 on [0, 5]
(b) g(x)= x+1 / x−1 on [2, 4]

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