Question

Find the slope of the tangent line to the cuve sqrt(7x+y) +
sqrt(3xy) = 11 at the point (3,4).

The slope of the tangent line to the curve at the given point
is:

Answer #1

Find the slope of the tangent line to the curve
sqrt(4?+3?) + sqrt(xy) = sqrt(29) + sqrt(15) at the point
(5,3).

Find the slope of the tangent line to the curve
−4x^2−3xy−2y^3=1
at the point (1,−1)(1,-1).

Find the slope of the line tangent to the curve y=x^2 at the
point (-0.9,0.81) and then find the corresponding equation of the
tangent line.
Find the slope of the line tangent to the curve y=x^2 at the
point (6/7, 36,49) and then find the corresponding equation to the
tangent line.
answer must be simplified fraction

Find the equations of the tangent and normal to the curve
x2 + y2+3xy-11 = 0 at the point x = 1, y =
2.

Find the general expression for the slope of a line tangent to
the curve of y = x^2 + 2 at the point P(x1, f(x1)) Then find the
slopes for x = 2 and x = -3 Sketch the curve and the tangent
lines.

Consider the equation: x^ 4 + 3xy^3 − y ^4 = 9x^2 y
a) find the points on the curve where x = 3
b) for each of the points found in pt. a find the slope of
tangent line at that point
c) for each of the points found in pt. a , write an equation for
the tangent line to the curve at that point.

Find an equation of the tangent line to the curve at the given
point.
1.) y= sqrt(5x+ 9), at x= 10.
2.) y= cos(x) + cos^3(x), at x=π/6.

Use implicit differentiation to find an equation of the tangent
line to the curve 3xy^3+4xy=56 at the point (8,1)

at
what point on the curve y=sqrt(1+2x) is the tangent line
perpendicular to the line 15x+3y=1

Find an equation for the line tangent to y=5-7x^2 at (2,-23)

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