Question

Use Newton's method with the specified initial approximation x1 to find x3, the third approximation to the root of the given equation. (Round your answer to four decimal places.) 2x^3 − 3x^2 + 2 = 0, x1 = −1

Answer 1

Newton's method to solve f(x)=0

Let f(x) is continuous function on [a,b]

Then solution in [a,b] is given by

Here

And it's derivative is