Question

Find the equations of ALL tangent lines to the curve x 2 + 4y 2 = 8 that pass through the point (−4, 0).

- I got to dy/dx = -x/4y Now that I have that i am stuck.

Answer #1

Determine the equations of the lines that are tangent to the
ellipse x2 + 4y2 = 16 and also pass through
the point (4,6)
[ANSWER: 2x -y + 10 = 0 and x=4]

Find equations of the tangent lines to the curve f (x) = (2x
+1)/(4x-3) that are perpendicular to the line 5x−2y+2=0.
Explanation would be appreciated!

Find equations of all lines having slope negative 1 that are
tangent to the curve y equals 1/x+9

I need to find the equations of the tangents to the ellipse 4x^2
+ y^2 = 72 which pass through the point (4,4). Seeing that (4,4) is
not on the ellipse, I need to find the equations of the tangents by
denoting the unknown point by (h, k). I used implicit
differentiation and found dy/dx = -4x/y and used that to denote the
slope, letting m = -4h/k. Now, when I substitute m into point slope
form I get a...

Sketch the curve y = x^2 + 5 , and the point (0,-6) on the
same
coordinates. Find the equations of the lines that pass through the
point
(0,-6) and tangent to the curve y = x^2 +5 at the point x = a.
(Hint there
are two values of a : a > 0 and a < 0 )

Find the lines that are (a) tangent and (b) normal to the curve
at the given point .
8. x^2+y^2=25,(-3,-4)
Tangent Line: ______________________ Normal Line:
_______________________

Consider the parametric curve defined by x = 3t − t^3 , y = 3t^2
. (a) Find dy/dx in terms of t.
(b) Write the equations of the horizontal tangent lines to the
curve
(c) Write the equations of the vertical tangent lines to the
curve.
(d) Using the results in (a), (b) and (c), sketch the curve for
−2 ≤ t ≤ 2.

What are the equations of the tangent and normal lines to the
following curve:
y2+y+x=arctan2(sin3(x)) at
point (0,1)
Remember that (arctan (u)=tan-1(u))

Find the equations for the tangent line and the normal line to
the curve x = sin^2 (xy)? at point ((1/2),(pi/2)).

differential equations solve
(2xy+6x)dx+(x^2+4y^3)dy, y(0)=1

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 3 minutes ago

asked 6 minutes ago

asked 8 minutes ago

asked 9 minutes ago

asked 12 minutes ago

asked 12 minutes ago

asked 13 minutes ago

asked 20 minutes ago

asked 28 minutes ago

asked 37 minutes ago

asked 43 minutes ago

asked 45 minutes ago