Use the Midpoint Rule with the given value of n to approximate the integral. Round the answer to four decimal places.
6e^−0.7t dt, n = 5, Integral is [1,2]
Then,
(Integral is [1,5]
5 | 3x2e−xdx, n = 4 |
1 |
i cant really read ur second problem . It is sort of diatorted. Sry
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