Question

solve the following: A) cos x = -(1/2) on [0, 2pi] B) sin x = (-sqrt 3)/2 on [0, 2pi].

Answer #1

Determine the solutions to the equation 2sinx - cos^2 x = sin^2
x for 0≤x≤2pi.

Solve for −?≤?≤?.
(a) cos x – sin x = 1
(b) sin 4x – sin 2x=0
(c) cos x−√3sin ? = 1

Solve the following
a) 2 cos^2(4x) + 5 cos(4x) + 2 = 0.
b) arctan(3x + 3) = π/4
c) 2^1+sin^2(x) = 4^sin(x)
d) ln(x + 3) = ln(x) + ln(3)

1, Solve cos(x)=0.17cos(x)=0.17 on 0≤x<2π0≤x<2π
There are two solutions, A and B, with A < B
2, Find the EXACT value of cos(A−B)cos(A-B) if sin A = 3434, cos
A = √7474, sin B = √91109110, and cos B = 310310.
cos(A−B)cos(A-B) =
3,
Find all solutions of the equation 2cosx−1=02cosx-1=0 on
0≤x<2π0≤x<2π
The answers are A and B, where A<BA<B
A=? B=?

Solve the following Differential equations
a) x sin y dx + (x^2 + 1) cos y dy = 0

Solve the following
a)y=tan^-1 (sqrt((x+1)/(x+2)
b)y=ln(sin^-1(x))
c)d/dx[sec^-1(x)]=1/(x(sqrt(x^2 -1)
d)Find Y' tan^-1(x^2 y)=x+xy^2

1) find the
absolute extrema of function f(x) = 2 sin x + cos 2x on the
interval [0, 2pi]
2)
is f(x) = tanx
concave up or concave down at x = phi / 6

Solve the given equation
2 cos^2 theta+sin theta =1
cos theta cos 20 + sin theta sin 20= 1/2

Solve the following differential equations
1. cos(t)y' - sin(t)y = t^2
2. y' - 2ty = t
Solve the ODE
3. ty' - y = t^3 e^(3t), for t > 0
Compare the number of solutions of the following three initial
value problems for the previous ODE
4. (i) y(1) = 1 (ii) y(0) = 1 (iii) y(0) = 0
Solve the IVP, and find the interval of validity of the
solution
5. y' + (cot x)y = 5e^(cos x),...

Evaluate each of the following limits. a) limx→∞(x/x − 2)^x
b) limx→0 sin x cos x/x + tan x

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