Question

Solve the equation y''-y'=-3 y(0)=0 and y'(0)=0 by using the method
of parameters and determinants

Answer #1

Solve the equation y''-y'=-3 y(0)=0 and y'(0)=0 by using the method
of undetermined coefficient.

Solve the differential equation using method of Undetermined
Coefficients. y'' + y = t^3, y(0) = 1, y'(0) = -1

) Solve the differential equation
dydt=
cos(t)y+sin(t)
using either the method of variation of parameters or the method of
integration factor. Clearly identify the integration factor or
parameter v(t) used (depending on which method you use).
Also identify the solution to the homogeneous equation, and the
particular solution. The use your solution to find the solution to
the IVP obtained by adding the initial condition y(0) = 1.

Solve the equation y''-y'=-3 y(0)=0 and y'(0)=0 by using laplace
transforms

Solve the following second-order equation applying variation of
parameters method:
y'' + 4y' + 4y = t^(-2) * e^(-2t) t > 0
Thank you!

Solve Differential equation by variation of parameters method.
y"-5y'+6y=e^x

Solve the following differential equation using the power series
method. (1+x^2)y''-y'+y=0

Solve the following equation by using the frobenius method
y ′′ + xy′ + (1 − 2 * x ^ (-2) )y = 0
No point is given.

By using method of variation of parameters the particular
solution of the following differential equation
y″+y=sec2(x)
is

Solve the following exercise using the Laplace method:
A) y''-5y'+6y=e^(4t), y(0)=1, y'(0)=-3

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