Question

Determine if the series converges conditionally, converges absolutely, or diverges. /sum(n=1 to infinity) ((-1)^n(2n^2))/(n^2+4) /sum(n=1 to...

Determine if the series converges conditionally, converges absolutely, or diverges.

/sum(n=1 to infinity) ((-1)^n(2n^2))/(n^2+4)

/sum(n=1 to infinity) sin(4n)/4^n

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