Question

Write an equation of the perpendicular bisector of JK, where J = (−8, 4) and K = (4, 4)

Answer #1

Slope of line JK is,

(4-4)/(4-(-8)) =0

Since , slope of line JK is zero,

This implies,

Slope of perpendicular bisector will be infinity or, undefined.

And , equation of line with infinity slope is given as,

x=c,

Where 'c' is a constant.

Now, to find 'c',

As mid point of line JK will meet at perpendicular bisector ,so x-coordinate of mid point of line JK will be the value of 'c',

And x - coordinate of mid point for line JK will be,

x- coordinate of mid point =(-8+4)/2 =-2

Therefore ,

Equation of perpendicular bisector is,

x=-2

Or,

x+2=0

Or,

Equation of perpendicular bisector is ,

x+2=0

Write an equation of the perpendicular bisector of JK, where J =
(−6, 3) and K = (3, 3).

Write the equation for the plane.
The plane through the point A(4, 8, 2) perpendicular to the vector
from the origin to A.

Write an equation in slope-intercept form a line that
is perpendicular to y = 3x-4 and that contains (-12, 2).
a. y = -1/3 + 2
b. y = -1/3 - 2
c. y = 3x + 26
d. y = 3x + 24

write the equation for flux (J).

8.3.59 Q 18
Write an equation of the line containing the given point and
perpendicular to the given line. Express your answer in the form y
= mx + b
(4,8); 6 x + y = 8
The equation of the line is y = ______.
(Simplify your answer. Use integers or fractions for any
numbers in the expression.)

1. (4, -3) (-8, 5) Linear equation in point slope
2. perpendicular to 2x-6y=12; (4,-2)
3. graph and shade 3y+ 2x =3

1.Find an equation for the plane that is perpendicular to the
line l(t) = (8, 0, 4)t + (5, −1, 1) and passes through (6, −1,
0).
2.Find an equation for the plane that is perpendicular to the
line l(t) = (−3, −6, 9)t + (0, 7, 1)and passes
through (2, 2, −1).

1. Consider
three
vectors:
(
8
marks)
C i j k
B i j k
A i j k
0ˆ 3 ˆ 5 ˆ
2ˆ 7 ˆ 1ˆ
4ˆ 6 ˆ 2 ˆ
= + +
= + −
= + −
!
!
!
1.1 Evaluate
D=
2A+B?
(2
marks)
1.2 Evaluate
2A•(-‐B)
(2
marks)
1.3 Find
the
angle
between
D
and
2C
using
cross
product
method
(4
marks

Solve this SHM, the m=2 m/s and k=8. Write a 2nd order differential
equation and give a general solution as sum of sin and cosine. then
give a specific solution as x intial is 2 and v intial is -4. What
time does it mass through equilibrium?

What is the vector product of A = 4 (i) - 3 (j) - 5 (k) and B =
5 (i) - 4 (j) + 2 (k)?
22
9 (i) - 7 (j) - 3 (k)
14 (i) - 17 (j) - 1 (k)
-26 (i) - 33 (j) - 1 (k)
20 (i) + 12 (j) - 10 (k))

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