Show that the AAS and ASA congruence theorems (Euclid I-26) fail in taxicab geometry.
Take A=(0,0), B=(1,1), C=(2,0) then form triangle
Now take D=(0,0),E=(0,1),F=(1,1) form triangle.
let suppose angle BAC= angle EDF=45 degree ; angle BCA=angle DFE=45 degree
also length of AC in taxicab geometry is (2-0)+(0-0)=2;
length of DF IS (1-0)+(1-0)=2;
so sides AC and DF have measure 2 and this gives condition of ASA test but these two triangles are not congruent because
measure of AB IS (1-0)+(1-0)=2
while measure of DE is (0-0)+(1-0)=1 and hence those two are not congruent triangle in Taxicab geometry.
Similarly you can construct triangle for AAS test fallcy in taxicab geometry.
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