Question

In the lab, Abdul has two solutions that contain alcohol and is mixing them with each other. He uses 4 times as much Solution A as Solution B. Solution A is 12% alcohol and Solution B is 18% alcohol. How many milliliters of Solution B does he use, if the resulting mixture has 132 milliliters of pure alcohol?

Answer 1

In solution A, alcohol : water = 12% : 88% = 3 : 22

In solution B, alcohol : water = 18% : 82% = 9 : 41

Now 4 times as much solution A is mixed with solution B that means "4x" of solution A is mixed with "x" of solution B.

Ratio of pure alcohol in solution A = 3/25

Ratio of pure alcohol in solution B = 9/50

3/25 * 4x + 9/50 * x = 132 ml

12x/25 + 9x/50 = 132 ml

(24x + 9x)/50 = 132 ml

33x/50 = 132 ml

x = (132 *50)/33 = 200 ml

The quantity of solution B used in the mixture is 200 ml. (Answer)