Let the numbers from 40 to 300 form an Arithmetic progression or a sequence.
The first term is 40 and the common difference is 1.
Let 300 be the nth term.
We will need to use the formula , an = a + (n - 1)d , where an is nth term, a = first term, d = difference
300 = 40 + (n - 1) * 1
==> 300 = 40 + n - 1
==> 300 = 39 + n
==> 300 - 39 = n
Hence n = 261
Hence 300 is 261th term.
The formula for finding sum of n terms of arithmetic progression is,
S261 = 44370
Hence sum of numbers from 40 to 300 is 44370.
Hope this will help you.
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