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Suppose in triangle ABC ma and mb are the lengthsof the medians from A and B...

Suppose in triangle ABC ma and mb are the lengthsof the medians from A and B respectively. Prove that if a≥b then ma≤mb (recall the convention that in triangle ABC, a=BC and b=AC

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please upvote my answer,, theta 2 > theta 1, because theta 2 is front of a= BC, and theta one is front of b, and give a>b, that implies theta 2> theta 1, if any things you not understand please ask me in comments section

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