Question
a) get the point of maximum curvature of y= x^ 2/3 b) get the equation of...
a) get the point of maximum curvature of y= x^ 2/3
b) get the equation of the line tangent to the curve
r(t)= (t/t^2+1, ln (t^2 + 1), tln(t)) in the point t=1
Homework Answers
Answer #1
Not the answer you're looking for?
Similar Questions
At what point does the graph of y = ln x have maximum curvature?
At
what point does the graph of y = ln x have maximum curvature?
Let y = x 2 + 3 be a curve in the plane. (a) Give a...
Let y = x 2 + 3 be a curve in the plane.
(a) Give a vector-valued function ~r(t) for the curve y = x 2 +
3.
(b) Find the curvature (κ) of ~r(t) at the point (0, 3). [Hint:
do not try to find the entire function for κ and then plug in t =
0. Instead, find |~v(0)| and dT~ dt (0) so that κ(0) = 1 |~v(0)|
dT~ dt (0) .]
(c) Find the center and...
Consider the equation: x^ 4 + 3xy^3 − y ^4 = 9x^2 y a) find the...
Consider the equation: x^ 4 + 3xy^3 − y ^4 = 9x^2 y
a) find the points on the curve where x = 3
b) for each of the points found in pt. a find the slope of
tangent line at that point
c) for each of the points found in pt. a , write an equation for
the tangent line to the curve at that point.
The curvature at a point P of a curve y = f(x) is given by the...
The curvature at a point P of a curve y =
f(x) is given by the formula below.
k =
|d2y/dx2|
1 + (dy/dx)2
3/2
(a) Use the formula to find the curvature of the parabola
y = x2
at the point
(−2, 4).
(b) At what point does this parabola have maximum curvature?
1) x = t^3 + 1 , y = t^2 - t , Find an equation...
1) x = t^3 + 1 , y = t^2 - t , Find an equation of the tangent
to the curve at the point corresponding to t = 1
2) x = t^2 + 1 , y = 3t^2 + t ,Find
a) dy/dx ,
b) (d^2)y / dx^2
c) For which values of t is the curve concave upward?
3) sketch the curve: r = 1 - 3cos θ
4)A demand curve is given by p = 450/(x...
Find an equation for the line tangent to the x^(3)+y^(3)= 9−x at the point (2,−1).
Find an equation for the line tangent to the x^(3)+y^(3)= 9−x at
the point (2,−1).
a) Find the equation of the tangent line to the curve x= 2sin2t, y= 3sint at...
a) Find the equation of the tangent line to the curve x= 2sin2t,
y= 3sint at the point where the same.
b) Find the points on the curve x= t^2-t+2, y=t^3-3t where the
tangent is horizontal.
Find the radius of the curvature of the following curve at the given point. Then write...
Find the radius of the curvature of the following curve at the
given point. Then write the equation of the circle of curvature at
the point. The radius of curvature at a point P is given by 1/k,
where k is the curvature at P
y=ln 2x at x=1/2
The radius of curvature at x=1/2 is 1/k = ?
The equation of the circle of curvature at this point is ?
Find an equation for the line tangent to the following curve at the point (4,1). 1−y=sin(x+y^(2)−5)...
Find an equation for the line tangent to the following curve at
the point (4,1).
1−y=sin(x+y^(2)−5)
Use symbolic notation and fractions where needed. Express the
equation of the tangent line in terms of y
and x.
equation:
At what point on the curve x = 3t^2 + 1, y = t^3 − 3...
At what point on the curve
x = 3t^2 + 1, y = t^3 − 3 does the tangent line have slope 1/2
?
ADVERTISEMENT
Need Online Homework Help?
Get Answers For Free
Most questions answered within 1 hours.
ADVERTISEMENT
Active Questions
asked 1 minute ago
asked 14 minutes ago
asked 16 minutes ago
asked 20 minutes ago
asked 25 minutes ago
asked 34 minutes ago
asked 39 minutes ago
asked 45 minutes ago
asked 46 minutes ago
asked 52 minutes ago
asked 1 hour ago
asked 1 hour ago