Question

Find an equation of the tangent plane to the surface z=1x^2+1y^2+1x+3y−3 at the point (4, 1, 21).

Answer #1

Find an equation of the tangent plane to the surface
z=−3x2−1y2−2x+1y−1 at the point (4, 2,
-59).
z=________

Find an equation of the tangent plane to the given surface at
the specified point.
z = 3x2 - y2 +
3y, (-3, 3, 27)

Find an equation of the tangent plane to the surface z = x^2 +
xy + 3y^2 at the point (1, 1, 5)

Find the equation of the tangent plane to the surface
z=e^(−2x/17)ln(3y) at the point (−2,4,3.1441).

Find an equation of the tangent plane to the given surface at
the specified point.
z = 2(x − 1)2 + 4(y + 3)2 +
1, (3, −1, 25)
Answer as z=

Find an equation of the tangent plane to the given surface at
the specified point. z = 8x^2 + y^2 − 7y, (1, 3, −4)

Find an equation of the tangent plane to the given surface at
the specified point.
z = 2(x − 1)2 + 4(y + 3)2 +
9, (2, −2, 15)

Find an equation of the tangent plane to the surface x y 2 + 3 x
− z 2 = 4 at the point ( 2 , 1 , − 2 ) An equation of the tangent
plane is

find the tangent plane to the surface x^2 + 2xy + z^3 = 4 at point
P (1,1,1)

Find an equation of the tangent plane to the given surface at
the specified point.
z = 2x2 +
y2 −
7y, (1, 3, −10)

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