Question

Find the equation of the tangent line to the function f(x)=8√(x)−6 at the point (64,58). Provide your answer in slope–intercept form of a linear equation, y=mx+b, where m is the slope and b is the y-intercept. Express m and b as exact numbers.

Answer #1

f(x) = (sin x)2(cos
x)5
a) Find the first derivative of your function in fully factored
form
b) Find the critical numbers over the domain
c) Find the exact slope of the tangent to your function at x=
4
d) Find the exact equation of the tangent to your function at x=
4 in slope y intercept form

Find the equation of the tangent line to the graph of the
function f(x)=(x^2+8)(x−2) at the point (1,−9).
I thought it was re-writen as (2x^2 + 8)(x-2) then plugging in 1
for x and solving. I came up withit in slope form y = -20x - 1 but
says im wrong. What steps did i miss?

Find the equation of the tangent line to the function f(x) =
ln(7x) at x=4.
(Use symbolic notation and fractions where needed. Let y = f(x)
and express the equation of the tangent line in terms of y and
x.)
equation:

Let f(x)=22−x2f(x)=22-x2
The slope of the tangent line to the graph of f(x) at the point
(−4,6) is .
The equation of the tangent line to the graph of f(x) at (-4,6) is
y=mx+b for
m=
and
b=
Hint: the slope is given by the derivative at x=−4

Find the equation of the tangent line to the curve y = 3 sec x -
6 cos x at the point (pi/3, 3). The equation must be written in y =
mx + b form
find m and b

Find the equation of the tangent line to the curve defined by
the equations x=tln(t), y=sin2(t) when t=1. Do not evaluate the
trigonometric functions, and include parentheses around their
arguments. Give your answer in slope-intercept form y=mx+b.

. Find the slope of the tangent line to f-1 at the
point P(-1, 0) if f(x) = x+1/ x-1, and then find the
slope-intercept equation of the tangent line to the graph of
f-1 at P.

4) Use implicit differentiation to find the equation of the
tangent line to the curve xy^3+xy=16 at the point (8,1). The
equation of this tangent line can be written in the form
y=mx+by=mx+b where m is:
and where b is:

Use Implicit Differentiation to find first dy/dx , then the
equation of the tangent line to the curve x2+xy+y2= 2-y at the
point (0,-2)
b. Determine a function of the form f(x)= ax2+ bx + c (that is,
find the real numbers a,b,c ) if the graph of the function has
slope 2 at the point (3,4) , and has a horizontal tangent where
x=1
c. Assume that x,y are functions of variable t satisfying the
equation x2+xy=10. Find dy/dt...

Find the slope of the line tangent to the curve y=x^2 at the
point (-0.9,0.81) and then find the corresponding equation of the
tangent line.
Find the slope of the line tangent to the curve y=x^2 at the
point (6/7, 36,49) and then find the corresponding equation to the
tangent line.
answer must be simplified fraction

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