Square EFGH is drawn on a coordinate plane. Diagonal GE is on the line y-3= 3(x+4). What is the slope of diagonal FH?
Answer to the above question -
we know that, Diagonals of square are perpendicular bisectors of each other.
And the slopes of two perpendicular lines are negative reciprocal of each other. This means that if a line is perpendicular to a line that has slope m, then the slope of the other line is -1/m.
Given, Slope of diagonal GE = 3 ( Equation of the line is in the form of y= mx + c. Here m is the slope.)
Then slope of diagonal FH = -1/3.
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