Complete the pattern: 2,5,10,17,___,____,____ and find Nth term in the sequence.
The differences between the successive terms of the given series are 3,5,7,…Apparently, these differences are in arithmetic progression.
If the initial term of such a series is a0 and if dn is the difference between the nth term and the (n+1)th term , then an = a0+(n-1)dn and dn= d0+(n-2)d where d0 is the difference between the 1st and the 2nd terms and d is the common difference in the arithmetic progression formed by the differences between the of the successive terms of the series {an}. Thus, an=a0+(n-1)[d0+(n-2)d] = a0+(n?1)d0+ (n?1)(n?2)d.
In case of the given series, d0 = 3 and d = 2 so that an = 2+3(n-1)+2(n-1)(n-2) = (3n-1)+ 2(n-1)(n-2). The series is 2,5,10,17,26,37,50,65,82,101,….
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