For critical points we set g_x=0 and g_y=0
=> 2x-2=0 and 6y=0
=> 2x=2 and y=0
=> x=1 and y=0
The critical point is (1,0)
; ;
for second derivative test
As D(1,0) >0 and g_xx(1,0)>0 then we have local minimum at (1,0)
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