Question

I cannot see it, I need a different pair of eyes. The tangents of the equation 4x^2+y^2=72 pass through (4,4) have an equation that look like this: y-k=-4h/k(x-h) since we know (4, 4) is on the tangent, we have 4-k=-4h/k(4-h). How on earth do we solve for (h, k)? My professor solved for h=21/5 and k=6/5 and I am trying to review and hitting a wall.

Answer 1