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Find the absolute maximum and absolute minimum values of f(x,y) = x^2 + 2y^2 − 2x...

Find the absolute maximum and absolute minimum values of f(x,y) = x^2 + 2y^2 − 2x + 2 on the closed disk D: x^2 + y^2 ≤ 4.

Answer: absolute min: f(1, 0) = 1; absolute max: f(−1, ± √3) = 11

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