Suppose that the demand and price for honeydew melons are related by the equation q = 5900 – 800 p , where q is in thousands and p is in dollars. What price will give the maximum revenue? What is the maximum revenue?
revenue = demand * price
= q * p
= (5900 - 800 * p) * p
= 5900 p - 800 p2
To maximize revenue we need to equate the derivative of this function to zero
d(revenue) / dp = 0
or, d/dp (5900p - 800p2) = 0
or, 5900 - 2 * 800 * p = 0
or, p = 3.6875
Maximum revenue = 5900 * 3.6875 - 800 * 3.68752 = 10878.125
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